Given ΔH° = -566. kJ
Work done , W = P x ΔV
                     Â
= 1 atm x (-24.5 L )
                    Â
= -24.5 L atm
                    Â
= -24.5x101
JÂ Â Â Â Â Â Â Â Â Â Â Â Â
Since 1 L atm = 101 J
                   Â
= -2.47x103 J
                   Â
= -2.47 kJ
From first law of thermodynamics , ΔH° = ΔE° + W
                                                 Â
ΔE° = ΔH° - W
                                                         Â
= -566 kJ - (-2.47 kJ)
                                                         Â
= -564 kJ
Therefore option (D) is correct