Find the distance between the following pair of points
(2,5) , (3,2)
Let P(2,5) and Q(3,2) be the given points,and the line is in straight line.
Here x1=2, y1= 5 and X2 =3 , y2=2
PQ =?(x2-x1)^2 + (y2-y1)^2
=?(3-2)^2 +(2-5)^2
=?1^2 + (-3)^2
=?1+9
=?10
Hence the distance between two points is ?10 units
Hence the distance between two points PQ is ?10 units
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