Find the value of polynomial 5x–8x^2+3 at the points
(i) x=–5
(ii)x=0
Solution:
The given polynomial is,
5x–8x^2+3 .... (A)Â
(i)To find the value at point x=–5
On substituting x=–5 in the polynomial given by (A) we get,Â
=5(–5)–8(–5)^2+3
=–25–8(25)+3
=–25–200+3
=–225+3
=–222
Â
(ii) Similarly, we can find the value of polynomial (A) at point x=0.
Substitute x=0 in the polynomial given by (A),Â
we have,Â
=5(0)–8(0)^2+3
=0–0+3
=3
The value of polynomial 5x–8x^2+3 at
(i) x=–5 is –222.Â
(ii) x= 0 is 3.Â
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