For 220.0 mL of a buffer solution that is 0.3028 M in
CH3CH2NH2 and 0.2783 M...
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For 220.0 mL of a buffer solution that is 0.3028 M inCH3CH2NH2 and 0.2783 M inCH3CH2NH3Cl, calculate the initialpH and the final pH after adding 0.0100 mol ofNaOH(Kb=5.6⋅10−4).
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3.6 Ratings (372 Votes)
1 Kb 56104 pKb log Kb log56104 3252 use pOH pKb log conjugate acidbase 3252 log 0278303028 322 use PH 14 pOH 14 322 1078 Answer 1078 2 mol of NaOH added 001
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