For an exposure of 43 R (Roentgen), calculate; a) The charge (in coulombs) liberated per kg...

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For an exposure of 43 R (Roentgen), calculate;
a) The charge (in coulombs) liberated per kg of air
b) The number of ion pairs liberated per kg of air
c) The energy absorbed per kg of air
d) The absorbed dose in air

Answer & Explanation Solved by verified expert

4.2 Ratings (619 Votes)

The question asked is about Dosimetry a Roentgen is a unit of exposure and named after Wilhelm Roentgen He discovered in the year 1895 the x rays The definition of 1 RRoentgen in terms of Coulombs per kilogram is 258 10 4 coulombs per kilogramC kg1 So 1 RRoentgen 258 10 4 C kg1 43 R Roentgen 43 258 10 4 C kg1 11094 104 C kg 1 0011094 C kg1 hence the charge in coulombs See Answer

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For an exposure of 43 R (Roentgen), calculate; a) The charge (in coulombs) liberated per kg...

50.1K

Verified Solution

Question

Basic Math

For an exposure of 43 R (Roentgen), calculate;
a) The charge (in coulombs) liberated per kg of air
b) The number of ion pairs liberated per kg of air
c) The energy absorbed per kg of air
d) The absorbed dose in air

Answer & Explanation Solved by verified expert

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For an exposure of 43 R (Roentgen), calculate; a) The charge (in coulombs) liberated per kg...

50.1K

Verified Solution

Question

Basic Math

For an exposure of 43 R (Roentgen), calculate;a) The charge (in coulombs) liberated per kg of airb) The number of ion pairs liberated per kg of airc) The energy absorbed per kg of aird) The absorbed dose in air

Answer & Explanation Solved by verified expert

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For an exposure of 43 R (Roentgen), calculate;
a) The charge (in coulombs) liberated per kg of air
b) The number of ion pairs liberated per kg of air
c) The energy absorbed per kg of air
d) The absorbed dose in air