For the circuit shown in the figure, calculate the following.(Assume  = 7.32 V and R = 5.70 Ω.)
A rectangular circuit begins at point a on its leftside. On its top side, the circuit splits into two parallelhorizontal branches.
- The top branch contains, from left to right, a 12.0 V batteryand a 4.00 Ω resistor. The positive terminal of the battery is tothe left of its negative terminal.
- The bottom branch contains a 2.00 Ω resistor.
The top and bottom branches recombine to meet at pointb, which is to the right of the branches. The right sideof the rectangular circuit extends down from the bottom branch,just to the right of the 2.00 Ω resistor and to the left of pointb. The bottom side of the rectangle, from right to left,contains a resistor R and a battery labeled emfℰ, where its positive terminal is to the right of itsnegative terminal. The circuit extends to the left from thenegative terminal until it reaches point a, completing thecircuit.
(a) the current in the 2.00-Ω resistor (Enter themagnitude.)
A
(b) the potential difference between points a andb,
ΔV =Vb −Va
V
