Solution:
Reaction and ICE
PCl5 (g) -- > PCl3 (g) + Cl2 (g)
IÂ Â Â Â Â Â Â Â Â Â
0.488
            Â
0.4900Â Â Â Â Â Â Â Â Â Â Â Â
0
CÂ Â Â Â Â Â Â Â
-x                   Â
+x                  Â
+x
EÂ Â Â Â Â Â Â Â Â
(0.488-x)Â Â Â Â Â Â Â Â
(0.4900+x)Â Â Â Â Â x
Kp = (0.4900 +x) x / (0.488 –x)
29.21 =(0.4900 +x)*x /(0.488-x)
x = 0.472
Lets find equilibrium pressure of all the species in above
equation.
Equilibrium partial pressure of Cl2 = 0.472 atm
PCl5 = 0.488 atm – 0.472 atm = 0.016 atm
PCl3 = 0.4900 + 0.472 = 0.96 atm
