the reaction is SO3(g) + NO ----> NO2(g)+SO2(g)
Kc = [SO2] [NO2]/ [SO3]*[NO]=0.5
[SO3][NO2]/ ]SO2] [NO2] =1/0.5= 2
since the coefficients in the numerator and denominator are
same. wther one takes moles or concentrations does not make any
difference
Moles                 Â
SO3Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
NOÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
NO2Â Â Â Â Â Â Â Â Â Â Â
SO2
Iniritial                   Â
0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.13Â Â Â Â Â Â Â Â Â Â Â Â
0.13
At
eq.                  Â
x                    Â
x                        Â
0.13-x        Â
0.13-x
x= moles of SO3 formed at equilibrium
Kc= 2= [SO3] [NO]/ [SO2][NO2] =
x2/(0.13-x)2 =2
taking square root gives
x/(0.13-x)= sqrt(2)= 1.44
x= 1.44*(0.133-x)
2.44x= 1.44*0.133
x= 0.0785
At equilibfrium [SO3] =[NO] =0.0785/3 =0.026 [SO2]
=(0.13-0.0.0785)/3=0.017167
