Cu(NO3)2(aq) +
Na2S(aq) → CuS(s) + 2
NaNO3(aq)
no of moles of Na2S = molarity * volume in L
                               Â
= 0.045*0.00375 = 0.000168moles
1moles of Na2S produce 1 mole of CuS
0.000168 moles of Na2S produce 0.000168 moles of CuS
mass of CuS =no of moles * gram molar mass
                 Â
= 0.000168*95.55 = 0.01605g
Cd(NO3)2(aq) +
Na2S(aq) → CdS(s) + 2
NaNO3(aq)
1 mole of na2S produce 1 moles of CdS
0.000168 moles of Na2S produce 0.000168 moles of CdS
mass of CdS = no of moles * gram molar mass
                    Â
= 0.000168*144.4 = 0.0242g
mass of Cu+2Â Â = 0.000168*63.5 = 0.01066g
of Cu+2
mass of Cd+2Â Â = 0.000168*112.4 = 0.0188g
of Cd+2
