For this problem, carry at least four digits after the decimalin your calculations. Answers may vary slightly due torounding.
A random sample of 5913 physicians in Colorado showed that 3062provided at least some charity care (i.e., treated poor people atno cost).
(a) Let p represent the proportion of all Coloradophysicians who provide some charity care. Find a point estimate forp. (Round your answer to four decimal places.)
(b) Find a 99% confidence interval for p. (Round youranswers to three decimal places.)
Give a brief explanation of the meaning of your answer in thecontext of this problem.
1% of the confidence intervals created using this method wouldinclude the true proportion of Colorado physicians providing atleast some charity care.99% of the confidence intervals createdusing this method would include the true proportion of Coloradophysicians providing at least some charitycare. 1% of all confidence intervals wouldinclude the true proportion of Colorado physicians providing atleast some charity care.99% of all confidence intervals wouldinclude the true proportion of Colorado physicians providing atleast some charity care.
(c) Is the normal approximation to the binomial justified in thisproblem? Explain.
No; np < 5 and nq > 5.Yes; np> 5 and nq > 5. No;np > 5 and nq < 5.Yes; np < 5and nq < 5.
