Four numbers have a sum of 9900. The second exceeds the first by
1/7 of the...
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Four numbers have a sum of 9900. The second exceeds the first by1/7 of the first. The third exceeds the sum of the first two by300. The fourth exceeds the sum of the first three by 300. Find thefour numbers.
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Let the first number x Second number x x7 8x7 Third number x 8x7 300 15x7
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