From the enthalpies of reaction H2(g) F2(g)2HF(g)H 537kJC(s) 2F2(g)CF4...

From the enthalpies of reaction H2(g)+F2(g)â†’2HF(g)Î”H=âˆ’537kJ C(s)+2F2(g)â†’CF4(g)Î”H=âˆ’680kJ 2C(s)+2H2(g)â†’C2H4(g)Î”H=+52.3kJ calculate Î”H for the reaction of ethylene with F2: C2H4(g)+6F2(g)â†’2CF4(g)+4HF(g)

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Chemistry

From the enthalpies of reaction H2(g)+F2(g)â†’2HF(g)Î”H=âˆ’537kJC(s)+2F2(g)â†’CF4(g)Î”H=âˆ’680kJ 2C(s)+2H2(g)â†’C2H4(g)Î”H=+52.3kJcalculate Î”H for the reaction of ethylene with F2:C2H4(g)+6F2(g)â†’2CF4(g)+4HF(g)

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4.0 Ratings (607 Votes)

H2(g)+F2(g)?2HF(g)?H=?537kJ

C(s)+2F2(g)?CF4(g)?H=?680kJ 2

C(s)+2H2(g)?C2H4(g)?H=+52.3kJ

2H2(g)+2F2(g)?4HF(g) Â Â ?H=?1074kJ

2C(s)+4F2(g)?2CF4(g) Â Â ?H=?1360kJ

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2C(s) + 2H2(g) +6F2(g) --------> 2CF4(g) + 4HF(g) ?H = -2434Kj

2C(s)+2H2(g ) Â Â Â Â Â Â Â Â ?C2H4(g)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ?H=+52.3kJÂ Â Â Â Â substract

(-)Â Â Â Â Â Â Â (-)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â (-)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â (-)

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C2H4(g)+6F2(g)?2CF4(g)+4HF(g)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ?HÂ Â Â = -2486

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From the enthalpies of reaction H2(g)+F2(g)â†’2HF(g)Î”H=âˆ’537kJ C(s)+2F2(g)â†’CF4(g)Î”H=âˆ’680kJ 2C(s)+2H2(g)â†’C2H4(g)Î”H=+52.3kJ calculate Î”H for the reaction of ethylene with F2: C2H4(g)+6F2(g)â†’2CF4(g)+4HF(g)

Free

80.2K

Verified Solution

Question

Chemistry

From the enthalpies of reaction H2(g)+F2(g)â†’2HF(g)Î”H=âˆ’537kJC(s)+2F2(g)â†’CF4(g)Î”H=âˆ’680kJ 2C(s)+2H2(g)â†’C2H4(g)Î”H=+52.3kJcalculate Î”H for the reaction of ethylene with F2:C2H4(g)+6F2(g)â†’2CF4(g)+4HF(g)

Answer & Explanation Solved by verified expert

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