Given a diprotic acid, H2A, with two ionization constants of Ka1
= 4.08× 10–4 and Ka2...
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Chemistry
Given a diprotic acid, H2A, with two ionization constants of Ka1= 4.08× 10–4 and Ka2 = 2.89× 10–12, calculate the pH and molarconcentrations of H2A, HA–, and A2– for each of the solutionsbelow. (a) a 0.167 M solution of H2A (b) a 0.167 M solution of NaHA(c) a 0.167 M solution of Na2A
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The reactions are H2A HA H Ka1 408104 HA A2 HKa2 2891012 Because Ka2 is very
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