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Given Hypothesis: Ho: population mean ?o = 200 Ha: population mean ?o < 200 This is...

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Given Hypothesis: Ho: population mean ?o = 200 Ha: populationmean ?o < 200 This is Left-Tailed test. Population StandardDeviation ? = 50. Given Significance Level is 0.10 (10%). Criticalz-value for 0.10 significance level and Left-Tailed test is(-1.28). Rejection Region will be to the left of z= - 1.28.-3…………..-2………….-1…………0……….1 Choose your sample mean, x? (anyinteger between 180 and 195) and your sample size, n, ( any integerbetween 16 and 36). Perform the steps below and reach yourconclusion: reject Ho or do not reject Ho. Steps to follow: 1.Calculate your test statistics z-value: z = ( x? - 200) / (50/?n)2. Compare your z value with the critical value -1.28. 3. If yourz-value is less than -1.28 (falls in Rejection Region) then rejectHo. If your z-value is greater than -1.28 (does not fall inRejection Region) then do not reject Ho. Show all three steps; justthe answer will not be graded.

Answer & Explanation Solved by verified expert
3.8 Ratings (476 Votes)

Ho :   µ =   200
Ha :   µ <   200

?=0.10

critical z value, z* =       -1.28

Rejection Region will be to the left of z= - 1.28


      

population std dev ,    ? =    50.0000                  
let Sample Size ,   n =    20                  
let Sample Mean,    x? =   185
                          
'   '   '                  
                          
1) Z-test statistic= (x? - µ )/(s/?n) = (   185 -   200   ) / (50/?20) =   -1.342

2) z stat < -1.28

3) reject Ho because z-value is less than -1.28 (falls in Rejection Region)
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