Given the data:PbO(s), Df Hq = -217.3 kJmol–1, Sq = +68.7 J mol–1K–1PbO2(s), Df Hq = -277.0kJ mol–1, Sq = +68.6 Jmol–1 K–1O2(g), Df Hq= 0.00 kJmol–1, Sq = +205 J mol–1K–1calculate the standard free energy change,DrGq, for the reaction:PbO(s) + ½ O2(g) ® PbO2(s)
Select one:
a. +1.45 kJ mol–1
b. –29.1 kJ mol–1
c. –68.3 kJ mol–1
d. –90.3 kJ m
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