how and dumpy interact such that flies who arehomozygous for the dumpy LOF mutation (dp) and heterozygous for thecomplete LOF mutation of how (h-) have wild type wings(normal length).
Mutants when dealing with only one gene(wildtype/normal phenotypes are dominant to mutantphenotypes):
dp/dp = truncated (short) wings
h-/h- = dies when trying to exit pupae
Mutants with the two genes interacting(wildtype/normal phenotypes are dominant to mutant phenotypes; soif there is even one dp+ allele they will have wildtype/normallength wings):
dp h+/ dp h+ = truncated wings that can fold down
dp h+ / dp h- = wild type wings (can fold down and are normallength)
dp h- / dp h - = dies when trying to exit pupae
You mate two wild type flies who are both carriers for thedumpy LOF mutation (dp) and the complete LOF howmutation (h-). They both have the same genotype: h- dp / h+dp+.
dumpy and how are 9 map units apart.If the cross produced 1000 larvae how many, on average,would grow up to have truncated wings? Remember, thecomplete loss of function mutant dies when coming out of its pupalcase, the larval stage is before the pupal stage.
Select one:
a. 2
b. 90
c. 0
d. 4.5
e. 9
