Dimethylmercury is (CH3)2Hg
Molar mass of (CH3)2Hg = 230.66
g
mass = 7.1 g
number of moles = mass /molar mass
                            Â
=7.1/230.66
                            Â
=0.031 mol
Number of molecules = Avogadro's number * number of
moles
                                   Â
= (6.022*10^23)*(0.031)
                                   Â
=1.854*10^22 molecules.
Answer: 1.854*10^22 molecules
number of moles of Hg in compound = 0.031
mol
molar mass of Hg = 200.59gm
mass of Hg = number of moles * molar mass of
Hg
                   Â
=0.031*200.59
                  Â
=6.22 gm
percentage of mercury = mass of mercury *100 / total
mass
                                      Â
= 6.22*100/7.1
                                      Â
= 87.6 %
Answer: 87.6 %