Hydrogen gas can be prepared by reaction of zinc metal with
aqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many...
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Hydrogen gas can be prepared by reaction of zinc metal withaqueous HCl: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) How many liters of H2would be formed at 636 mm Hg and 17 ∘C if 27.0 g of zinc wasallowed to react? How many grams of zinc would you start with ifyou wanted to prepare 6.85 L of H2 at 284 mm Hg and 28.5 ∘C?
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Zns2HClaqZnCl2aqH2g from this balanced equation it is clear that one mole of Zn will give one mole of H2 gas right now calculate the no ofmoles of Zn weight of Zn
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