(I already have part A but still still include it anyways so youcan use its data to solve for parts B and C.
Chemical energy is released or absorbed from reactions invarious forms. The most easily measurable form of energy comes inthe form of heat, or enthalpy. The enthalpy of a reaction can becalculated from the heats of formation of the substances involvedin the reaction:
ΔH∘rxn=ΔH∘f(products)−ΔH∘f(reactants)
Entropy change, ΔS∘, is a measure of the number of energeticallyequivalent microstates introduced into the system during thereaction. The degree of spontaneity of a reaction is represented bythe Gibbs free energy, ΔG∘. The Gibbs free energy depends on boththe enthalpy and entropy changes that take place during thereaction:
ΔG∘=ΔH∘−TΔS∘
where T is standard temperature, 298 K.
Part A
Part complete
Calculate the standard enthalpy change for the reaction
2A+B⇌2C+2D
where the heats of formation are given in the followingtable:
Substance | ΔH∘f (kJ/mol) |
A | -261 |
B | -425 |
C | 175 |
D | -491 |
Express your answer in kilojoules.
ΔH∘rxn = 315 kJ Â
Part B
For the reaction given in Part A, how much heat is absorbed when3.30 mol of A reacts?
Express your answer numerically in kilojoules.
Part C
For the reaction given in Part A, ΔS∘rxn is 41.0 J/K . What isthe standard Gibbs free energy of the reaction, ΔG∘rxn?
Express your answer numerically in kilojoules.