I have a normal process (Anderson-Darling pvalue=.54 and skew=.3. The median The R chart is out of...

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I have a normal process (Anderson-Darling pvalue=.54 and skew=.3. The median
The R chart is out of control (1 outlier). This means that theprocess variability is unstable, and the control limits on the xbarchart are unreliable. The process is not stable over time. What ifanything does this have to do with choosing the center of thedistribution? Use the median in this instance. Outliers will notaffect median as much as the mean. That is my best guess.

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Mean and Rchart used to describe observed central value and spread with respect to time respectively It is given that the R chart is out of control which shows that process variability is not stable and the control limits of the xbar See Answer

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I have a normal process (Anderson-Darling pvalue=.54 and skew=.3. The median The R chart is out of...

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Basic Math

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