I have a question about difference between physical observablesand eigenstates in quantum mechanics
it is postulated in Quantum Mechanics that
physical observable in Classical Mechanics are represented bylinear operators
the state of the particle was represented by a curve in phasespace determined by generalized position and momentum
but in Quantum Mechanics it is represented by a vector inHilbert space
and if we measure the physical observable of the particle, theprevious state of the particle once superpositioned witheigenstates of the physical observables
with the corresponding weighting factor(square of it isprobability of yielding the result when measure) collapses to asingle eigenstate and gives out the corresponding eigenvalue
but I don't understand what is the difference between physicalobservable represented by linear operator and the eigenstate of theparticle
