If the surface area of the Pacific Ocean is 1.6176 x 10^8 km^2 and the average...

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If the surface area of the Pacific Ocean is 1.6176 x 10^8 km^2and the average depth is 4,080 meters, how many moles of water inthe Pacific?

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Surface qrea of the pacific ocean = 1.6176*10⁸km²Â Â

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â KmÂ Â Â Â Â Â Â Â Â = 1000m

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.6176*10⁸ *(1000m)²

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.6176*10¹⁴ m²

Â Â Â Â Â Â Â Â Â Â Â Â Â depthÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 4080 m

volumeÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = area * depth

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.6176*10¹⁴ * 4080

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.599*10¹⁷ m³

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.610¹⁷ LÂ Â Â Â = 6.6*10²⁰ ml

mass of waterÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = volume * density of waterÂ Â Â Â Â Â Â Â Â Â Â Â Â [density of water = 1g/ml]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.6*10²⁰ *1

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.6*10²⁰

no of moles of H2OÂ Â Â Â Â Â Â Â Â Â Â Â Â = W/G.M.Wt

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 6.6*10²⁰/18

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.6*10¹⁹ moles

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If the surface area of the Pacific Ocean is 1.6176 x 10^8 km^2 and the average...

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Chemistry

If the surface area of the Pacific Ocean is 1.6176 x 10^8 km^2and the average depth is 4,080 meters, how many moles of water inthe Pacific?

Answer & Explanation Solved by verified expert

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