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  3. in a certain operation 3.54*104 kg of ticl4 is rea

in a certain operation 3.54*104 kg of Ticl4 is reacted with 1.13*104 kg of Mg A) Calculate...

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Chemistry

in a certain operation 3.54*104 kg of Ticl4 isreacted with 1.13*104 kg of Mg

A) Calculate the theoretial yield of titanium , Ti inkilograms.

B ) Calculate the percent yield if 7.91*103 kg of Ti isactually obtained

(Ti : 47.88 , Mg: 24,3, Cl; 35.5)

Help please with explain every thing :)

Answer & Explanation Solved by verified expert
3.7 Ratings (620 Votes)

A. Mass of TiCl4=3.54*104 kg

                Moles of TiCl4=3.54*104/189.88=186.433 kmol

                Moles of Mg=1.13*104/24.3=465.02 kmol

                Reaction occurring is:

                TiCl4 +2Mg =2MgCl2 +Ti

                As moles of Mg> 2*moles of TiCl4 hence TiCl4 is limiting reagent.

                Moles of Ti produced=Moles of TiCl4=186.433 kmol

                Theoretical yield of Ti= 47.88*186.433=8926.3 kg=8.9263*103 kg

B. Percent yield=(Actual yield/Theoretical yield)*100

                                =(7.91*103/8.9263*103)100=88.7%
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