In a lab, we are required to make a 100ml solution that contain:
54.30mg/L sodium salicylate,...
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In a lab, we are required to make a 100ml solution that contain:54.30mg/L sodium salicylate, 0.020M FeCl3, 0.050 M HCl. I will alsoneed to create a blank solution that contains 0.020 M FeCl3 and0.050 M HCI. The blank solution is also 100.00 mL. At the end, weare required to get an absorbance at 520 nm. What should I do toprepare the solutions? Please give detailed instructions. Thank youvery much!
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Step 1 Do the calculations for 100 mL solution a sodium salicylate 5430 mg L 543 mg in 100 mL b 0050 M HCl To prepare 100 mL of 005 M HCl Assuming molarity of concentrated HCl 1165 Using M1V1 M2V2 equation 1 Where M1 molarity
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