In a large city, a transportation engineer wants to estimate the proportion of residents who...
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In a large city, a transportation engineer wants to estimate the proportion of residents who use the bus system regularly. Out of a random sample of 2000 residents, 1220 use the bus regularly. Construct and interpret the 99% confidence interval.(P-hat) = 1220 / 2000 = .61(Q-hat) 1-.61 = .39Standard Error = .010906with a Z score of 2.5758 for the 99% confidence interval..61 +2.5758 (.010906) = .6380.612.5758 (.010906) = .5819(.5819, .6380)So with a confidence interval of 99%, the true proportion of residents who use the bus system regularly is between 58.19% and 63.8%
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