In a random sample of five mobile​ devices, the mean repair costwas ​$90.00 and the standard deviation was ​$11.00. Assume thepopulation is normally distributed and use a​ t-distribution tofind the margin of error and construct a 95​% confidence intervalfor the population mean. Interpret the results.
The 95​% confidence interval for the population mean​(76.34,103.66).
​(Round to two decimal places as​ needed.)
The margin of error is ​$____?? I NEED THIS ANSWER, OREXPLAINED HOW TO FIGURE THIS PART OUT PLEASE
​(Round to two decimal places as​ needed.)
