In a study of cell phone usage and brain hemispheric​ dominance,an Internet survey was​ e-mailed to 6980 subjects randomly selectedfrom an online group involved with ears. There were 1332 surveysreturned. Use a 0.01 significance level to test the claim that thereturn rate is less than​ 20%. Use the​ P-value method and use thenormal distribution as an approximation to the binomialdistribution. Identify the null hypothesis and alternativehypothesis. A. Upper H 0​: pequals0.2 Upper H 1​: pless than0.2 B.Upper H 0​: pgreater than0.2 Upper H 1​: pequals0.2 C. Upper H 0​:pequals0.2 Upper H 1​: pgreater than0.2 D. Upper H 0​: plessthan0.2 Upper H 1​: pequals0.2 E. Upper H 0​: pequals0.2 Upper H1​: pnot equals0.2 F. Upper H 0​: pnot equals0.2 Upper H 1​:pequals0.2 The test statistic is zequals nothing. ​(Round to twodecimal places as​ needed.) The​ P-value is nothing. ​(Round tothree decimal places as​ needed.) Because the​ P-value is ▼ greaterthan less than the significance​ level, ▼ reject fail to reject thenull hypothesis. There is ▼ insufficient sufficient evidence tosupport the claim that the return rate is less than​ 20%.
