Step 1we know that if function is a solution to the initial valueproblem than it must satisfies the differential equation andinitial conditionwe have y t3 and y0 5we havewe can say that yt is a solution of the differential equationof it satisfies the differential equation y t3we can write1Lets assume that y 15t4 5 hence we can saythatPut it in equation 1 we can say thatStep 2There might be a typo
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