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In the vertices of a square of side 2x10 ^ -7 four protons are placed. A...

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Physics

In the vertices of a square of side 2x10 ^ -7 fourprotons are placed. A fifth proton is initially perpendicular tothe square at its center at a distance of 2x10 ^ -9 m from it.Calculate (a) the minimum initial velocity of the fifth proton youneed to get to the center of the square (b) your initial and finalaccelerations. (c) graph the potential energy of the proton as afunction of its distance from the center of the square.

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SolutionaElectrostatic potential    See Answer
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