In triangle PQR right-angled at Q , PQ = 3 cm and PR = 6 cm
tan p = Opposite side / Adjacent side
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Using Pythagorean theorem,
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PR2 = PQ2 + QR2
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62 = 32 + QR2
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36 - 9 = QR2
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QR2 = 27
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QR = 3√3
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tan p = PQ/QR
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tan p = 3/√3
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Multiplying both numerator and denominator by √3, we get
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tan p = √3
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 ∠QPR = 60°