Let f be a continuous function on the closed interval [0,1] with
a range also contained...
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Let f be a continuous function on the closed interval [0,1] witha range also contained in [0,1]. Prove that f that there exists anx in [0,1] such that f(x)=x. Is the same explanation still valid iff is not continuous?
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INTERMEDIATE VALUE THEOREM Suppose that f ab R be continuous such that fafb 0 Then thereis an x
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