Let in a binomial distribution consisting of 5 independent trials probabilities of exactly 1 and...
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Let in a binomial distribution consisting of 5 independent trials probabilities of exactly 1 and 2 successes be 0 4 and 0 6 respectively Then the probability of getting exactly 3 successes is equal to O 2160 74 O 4320 74 O 4320 75 O 2160 75
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