M, a solid cylinder (M=1.35 kg, R=0.117 m) pivots on a thin,fixed, frictionless bearing. A string wrapped around the cylinderpulls downward with a force F which equals the weight of a 0.670 kgmass, i.e., F = 6.573 N. Calculate the angular acceleration of thecylinder. Tries 0/10 If instead of the force F an actual mass m =0.670 kg is hung from the string, find the angular acceleration ofthe cylinder. Tries 0/10 How far does m travel downward between0.450 s and 0.650 s after the motion begins? Tries 0/10 Thecylinder is changed to one with the same mass and radius, but adifferent moment of inertia. Starting from rest, the mass now movesa distance 0.470 m in a time of 0.510 s. Find Icm of the newcylinder.
