M, a solid cylinder (M=1.71 kg, R=0.133 m) pivots on a thin,fixed, frictionless bearing. A string wrapped around the cylinderpulls downward with a force F which equals the weight of a 0.690 kgmass, i.e., F = 6.769 N. Calculate the angular acceleration of thecylinder.
5.95×101 rad/s^2
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If instead of the force F an actual mass m = 0.690 kgis hung from the string, find the angular acceleration of thecylinder.
How far does m travel downward between 0.730 s and 0.930 s afterthe motion begins?
The cylinder is changed to one with the same mass and radius,but a different moment of inertia. Starting from rest, the mass nowmoves a distance 0.379 m in a time of 0.470 s. FindIcm of the new cylinder.
