Ans. Given,
          Â
Volume of solution = 25.0 mL = 0.025
LÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
; [1 mL = 0.001 L]
          Â
Molarity of solution = 10.0 mM = 0.010
MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
; [1 mM = 0.001 M]
Now,
          Â
Required moles of MOPS = Molarity x Volume of solution in
liters
                                              Â
= 0.010 M x 0.025 L
                                              Â
= (0.010 mol/ L) x 0.025
LÂ Â Â Â Â Â Â Â Â Â Â Â Â Â
; [1 M = 1 mol/ L]
                                              Â
= 0.00025 mol
Required mass of MOPS = Required moles x Molar
mass
                                  Â
= 0.00025 mol x (209.0 g/ mol)
                                  Â
= 0.05225 g