Marvin was standing on the roof of his house throwing waterballoons onto people on the sidewalk below. (Do not try this athome.) When he let the balloon go the balloon was 45 cubits off ofthe ground. He learned through trial and error that in order to hitsomeone on the ground he had to have the balloon reach a maximumheight of 55 cubits off of the ground 2 seconds after he threw it.Let h left parenthesis t right parenthesis be the height of thewater balloon in cubits t seconds after it was thrown. Assume thatheight is a quadratic function of time. (Note: A cubit is ameasurement of distance. Since we are not using feet or meters youcannot use standard physics formulas to solve this.) a) Find aformula for h left parenthesis t right parenthesis . b) Find thetime when the balloon hits the ground. Answer this question using acomplete sentence in terms of this problem.