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Melanie used cross multiplication to correctly solve a rational equation. She found one valid solution...

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Melanie used cross multiplication to correctly solve a rational equation. She found one valid solution and one extraneous solution. If 3 is the extraneous solution, which equation could she have solved? A. The equation is 4/(x-3)=x/10 because 3 makes a denominator equal to zero and is not a solution of the equation derived from cross multiplying.B. The equation is (x-3)/4=2x/4x because 3 makes a numerator equal to zero and is not a solution of the equation derived from cross multiplying.C. The equation is 8/(x^2-9)=5/(2x-6) because 3 makes a denominator equal to zero and is not a solution of the equation derived from cross multiplying.D. The equation is 8/(x+3)=12/4x-3 because 3 is a soluiton of both the original equation and equation derived from cross multiplying.

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