For the given reaction -
               Â
SCl2(g)Â Â +Â Â 2
C2H4 (g) <-->
S(CH2CH2Cl)2 (g).
I(M)Â Â Â Â Â Â
(0.258/5)Â Â Â Â Â Â
(0.592/5)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0
CÂ Â Â Â Â Â Â Â Â Â Â Â Â
-(0.0349/5)Â Â Â Â -
2(0.0349/5)Â Â Â Â Â Â Â +0.0349/5
Eq       Â
0.04462Â Â Â Â Â Â Â Â Â Â Â
0.104Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.00698
Thus -
At equilibrium -
[SCl2] = 0.04462 M , [C2H4] = 0.104,
[S(CH2CH2Cl)2 ] = 0.00698 M
If we convert it in to pressures by using P = CRT (P= nRT/V)
P(SCl2) = (0.04462)(0.0821)(293) = 1.0733
atm
P(C2H4) = (0.104)(0.0821)(293) = 2.50 atm
P(S(CH2CH2Cl)2) = (0.00698)(0.0821)(293) =
0.167 atm
Hence - Kp = P(S(CH2CH2Cl)2) /
(P(C2H4))2 * P(SCl2) =
(0.167) / (1.073)(2.50)2 = 0.0249
