N2 + H2 <=> 2NH3 Given inpart A: Kp = 1.64x10-4 at 673K and they asked what isthe Kc value, I got 5.38x10-8.
Now they are asking in Part B, qith 105 moles N2 and 318 molesH2 in a 400L gas chamber, how much ammonia would be produced?.... Iset up and ICE table with the Es equaling: E N2= 105-1x,E H2= 318-3x and E NH3 = +2x
following I Set up this, Kc=1.64x10-4(2x)2/(105-1x)(318-3x)3 ....Ibelieve to solve for X or NH3a quadratic formula is to be used now, how wouldyou solve for this problem/ Set it up?
