NO3-(aq)+4H+(aq)+3e->NO(g)+2H2O(l)E=0.96V
ClO2(g)+e->ClO2-(aq)E=0.95V
Cu2+(aq)+2e->Cu(s)E=0.34V
2H+(aq)+2e->H2(g)E=0.00V
Pb2+(aq)+2e->Pb(s)E=-0.13V
Fe2+(aq)+2e->Fe(s)E=-0.45V
Use appropriate data to calculate E?cell for thereaction.
3Cu(s)+2NO3-(aq)+8H+(aq)->3Cu2+(aq)+2NO(g)+4H2O(l)
Express your answer using two decimalplaces.
