On a trip, you get stuck in slow traffic and have to drive 90.0km at 30.0 km/hr. Then the traffic clears up, and you're able todrive another 90.0 km at 60.0 km/hr.
a) Calculate your overall average speed for this 180.0 km trip.Check: it's not 45.0 km/hr! See the next question as well. Use thedefinition of average speed in physics.
b) Prove that if you'd driven 180. km at 60.0 km/hr for thesecond leg, your overall average speed would have been 45.0km/hr.
c) In the original description of the trip, why was your overallaverage speed lower than 45.0 km/hr, the mathematical average of30.0 km/hr and 60.0 km/hr?
d) Determine the speed at which you'd have to have driven thesecond 90.0 km so that your overall average speed would have been45.0 km/hr.
e) What are the largest and smallest possible average velocitiesfor this trip, as originally described? What further informationwould allow you to determine where in this range your actualaverage velocity was? Explain in practical terms.
