Once the stock solutions are prepared, describe how you wouldproduce your buffers (four). Your explanation should be detailedand quantitative.
For my stock solution:
KH2PO4 = (136.08 g/mol)(1M)(100.00ml/1000ml)= 13.608 gm
           K2HPO4 = (174.17 g/mol)(1M)(100.00ml/1000ml)= 17.4178 gm
KH2PO4= (136.08 g/mol)(1M)(250.00ml/1000ml)= 34.02 gm
K2HPO4= (174.17 g/mol)(1M)(250.00ml/1000ml)= 43.54 gm
           KH2PO4= (136.08 g/mol)(1M)(25.00ml/1000ml) = 3.402 gm
           K2HPO4= (174.17 g/mol)(1M)(25.00ml/1000ml) = 4.35425 gm
KH2PO4= (136.08 g/mol)(1M)(10.00ml/1000ml)= 1.3608 gm
K2HPO4= (174.17 g/mol)(1M)(10.00ml/1000ml)= 1.74178 gm
           KH2PO4= (136.08 g/mol)(1M)(5.00ml/1000ml)= 0.6804 gm
           K2HPO4= (174.17 g/mol)(1M)(5.00ml/1000ml)= 0.87085 gm
