A = ECl
A = absorbance
E = molar absorptivity ,
C = concentration of material =
l = length of sample tube = 1 cm
Concentration of Oxy-myoglobin = A/El
                             Â
= 0.769/(12,800*1)
                            Â
= 6.008*10^-5 M
Concentration of met-myoglobin =
0.346(17900*1)
            Â
= 1.933*10^-5 M
No of moles of Oxy-myoglobin in 10 grams
sample
   = M* V = 6.008*10^(-5)*0.003 =
1.8024*10^-7 mole
no of moles in 1 gram meat = 1.8024*10^-7/10 =
1.8024*10^-8 mole
No of moles of met-myoglobin in 10 grams
sample
   = M* V = 1.933*10^(-5)*0.003 =
5.799*10^-8 mole
no of moles in 1 gram meat = 5.799*10^-8/10 =
5.799*10^-9 mole
