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  3. part a consider the second-order reaction: 2hi(g)�

Part A Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Rate law: k[H]^2 k= 6.4*10^-9 (mol*s) at 500 K Initial rate = 1.6...

60.2K

Verified Solution

Question

Chemistry

Part A

Consider the second-order reaction:

2HI(g)→H2(g)+I2(g)

Rate law: k[H]^2

k= 6.4*10^-9 (mol*s) at 500 K

Initial rate = 1.6 * 10^-7 mol (l*s)

What will be the concentration of HI after t =3.65×1010 s ([HI]t) for a reaction startingunder this condition?

Part B

In a study of the decomposition of the compound X via thereaction

X(g)⇌Y(g)+Z(g)

the following concentration-time data were collected:

Time (min)[X](M)
00.467
10.267
20.187
30.144
40.117
50.099
60.085
70.075

Given that the rate constant for the decomposition ofhypothetical compound X from part A is 1.60 M−1⋅min−1,calculate the concentration of X after 14.0 min .

Part C

The following data were collected for the rate of disappearanceof NO in the reaction2NO(g)+O2(g)→2NO2(g):

Experiment[NO](M)[O2](M)Initial Rate (M/s)
10.01260.01251.41×10−2
20.02520.02501.13×10−1
30.02520.01255.64×10−2

What is the rate of disappearance of NO when [NO]=6.15×10−2 M and [O2]=1.75×10−2 M ?

Part D

What is the rate of disappearance of O2 at the concentrationsgiven in part (c)?

Part E

A certain reaction with an activation energy of 175 kJ/mol wasrun at 515 K and again at 535 K . What is the ratio of fat the higher temperature to f at the lowertemperature?

Usef=e^−Ea/(R⋅T)

Answer & Explanation Solved by verified expert
4.2 Ratings (524 Votes)
Part A given rateKHI2 If initial rate16107 mol L s then HIoinitial concentration initial rateK12 sqrt 16107 mol L s64109 Lmol S50 molL using rate equation for second order Kt1HIo1HIt 64109 Lmol S 3651010 s150 molL1HIt solving    See Answer
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