a)
number of moles of benzoic acid = mass/ molar
mass
                                              Â
  = 0.9862 / 122.12
                                    Â
        =8.076*10^-3
mol
Heat released = 3226.7 KJ/mol*8.076*10^-3
mol
            Â
= 26.06 KJ
Q = C*(Tf-Ti)
26.06 KJ = C* (25.67 – 21.84) oC
C = 6.804 KJ/oC
Answer: 6.804 KJ/oC
b)
Q = C*(Tf-Ti)
  = 6.804*(22.28 – 21.22)
  =7.212 KJ
number of moles of glucose= mass/molar mass
                         Â
= 0.4654 / 180
                                    Â
  = 2.586*10^-3 mol
delta H = -Q/number of mol
    = - 7.212 KJ
/(2.586*10^-3)mol
    = -2789.3 KJ/mol
Answer: -2789.3 KJ/mol
