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please answer 8-10 all the info is given in the pictures. 1-7 have already been answered.

8. Take a sample of 30 females from your data a. Show your sample b. Find the proportion of female cat owners out of these females 9. Take a sample of 30 males from your data a. Show your sample b. Find the proportion of male cat owners out of these males 10. Using the results of #8 and #9, test the claim that females have a higher proportion of cat ownership than males. a. State the null and alternative b. State the test statistic c. Use the p-value to make a decision (reject or fail to reject) d. Graph the test statistic, p-value, and a=0.05 e. Write your conclusion in terms of the problem Out of 117 People, only 42 People own cuts. I am going to use a systematic sampling 7 technique to draw a sample size of 30, starting from the second observation and ! 1) No Z) No 3) Yes 4) No 5) No 6) No 7) Yes 8) No 9) No 60) Yes 11) No 12) No 13) No 14) No 13) Yes IC) No 11) No ) No 19) Yes 20) No 21) No 22) No 23) No 24) Yes 25)Yes 26) No 27)No 28) Yes 29) No 30) No 31) No 32) Yes 33) No 34) Yes 35)No 36) No 57) Yes 38) No 39) No 40) No 41) Yes 42) No 43) Yes 44)No 45)80 46) Yes 47) No 43) Yes (41) No 50)NO 2) In this Sample 15 out of 50 People 4) Margin of Error = 1.96*10.3+0.7 own Cats, Proportion of Cat owners 30.127) 50 in the sample = 15-0.3 Confidence interval is expected to contain the the population proportion (3) 95%. Confidence internal is (Pt 26,95 st) 95 of the times. Only less than where Margin of Emor, M.E is 20.95*5.E 5% of the confidence interval is repeated sampling may not contain the true 5) Based on the sample it is hard to make population me such a belief. Again for the sake of doing. A) I believe that b5s of the People own cats, based on the belief in question 5,45% do not Cats, 6) My belief cannot be justified as the proportion is not contained in confidence interval calculated in question 3 c) According to the statement both evento (owning cuts and not owning Cats) are equally likely. It is 50% chance of owning the cat. Based on the population that I got in question 2 it doesn't look like they are equal. Dwn 7) To test Ho : P = 56% against H.P750s at br level of significance. The test statistic used in Z- P-P Where P in sample proportion &q=1-p&h=30 6) 2= 0.3-0.5 To 5x0.5 = 283 C) the quale which corresponds 50 to the zvate in 0.004620.05. The null hypothesis Can be rejected and a 5% alpha use conclude that the Proportion of cat owners is not obor bo% c) the critical wave from the d) Standard normal table at 5% level of significance is 11.96 of the test statistic, 2 vale is inside the interval. We would! have falled to reject the null -2.85 -1.96 hypothesis. The rejection region falls on the two extention of the test Statistic, which is shown in the graph above the value gets equally divided into two and show in the tails of distribution of test Statistic. 0.0023 0.0023 U 1.96 2.83 Benchmark 5- Cats and Dogs 1. From the sample of 50 you took from the previous benchmark (or you can just take a new sample of 50) record whether they owned a cat or not. You can use the table below, make another one, or use excel: 2. Find the proportion of people who own cats from this sample. 3. Create a 95% confidence interval for the true population proportion of cat owners based on your sample. In words write what the confidence interval means in terms of our data. 4. Find the margin of error for your confidence interval 5. If I believe that people are just as likely to own a cat than to not own a cat a. What do I believe the proportion or percentage of cat owners is? (For example is it 0.20 or 20% are cat owners? Or some other percentage?) b. Looking at the proportion from part (a), do you believe it is possible that the true proportion of cat owners is what I am claiming? Why or why not? (is it in the interval you made?) 6. Again I claim that people are just as likely to either own a cat or not own a cat. Based on the proportion you found in #2 do you believe I am correct? Or do you think the true proportion is more? Is it less? 7. Test my claim that people are just as likely to either own a cat or not versus what you stated in #6. Or if you believed that I am correct test my claim against the proportion just being different (not equal to my claim) than my claim. Use a significance level of a = 0.05. a. State the null and alternative b. State the test statistic Use the p-value to make a decision (reject or fail to reject) d. Graph the test statistic, p-value, and a e. Write your conclusion in terms of the problem C. Age Sex F M M M Own Cat Yes No No No Yes Yes F F Yes F M F M Own Dog Yes Yes Yes No No No Yes Yes No No No No No Yes F M F F No M M F M F No Yes No Yes No Yes Yes No No Yes No Yes Yes Yes No Yes No Yes No No No Yes Yes Yes No No No No No No Yes F F M F M F M M M F 64 75 55 36 64 56 60 23 59 75 62 30 55 58 41 25 64 32 57 62 64 67 57 40 58 53 53 23 55 64 56 19 19 58 58 69 40 55 No No Yes Yes Yes Yes No No Yes Yes No Yes No No No Yes Yes F Yes F M M M M M M F No Yes No Yes Yes F No Yes M M M M M M F M F F Yes No No No No No No Yes No Yes Yes Yes Yes Yes No Yes No No Yes No No No No No No No Yes Yes No No Yes No No No Yes No No Yes No No No 63 25 44 75 58 50 55 64 71 57 22 19 18 28 57 18 64 50 24 38 31 54 69 26 M M M M M M M M M F F No No F M F F M M No Yes No No No Yes Yes Yes Yes Yes No No Yes No No No No No Yes Yes Yes No No No No No 45 22 35 65 74 32 18 42 23 37 21 30 25 28 27 F F F M F F M No No No Yes No No Yes Yes Yes No Yes No No No F F F M Yes No No F F F M M F F F F M F F M M F F M No No Yes No No No Yes Yes No No No No Yes No No Yes Yes No No Yes No No No No No Yes No No Yes No No No No No No Yes No No No Yes Yes Yes No No No No Yes Yes Yes Yes Yes 69 26 44 45 22 35 65 74 32 18 42 23 37 21 30 25 28 27 37 33 40 70 20 26 38 43 42 49 22 28 39 53 67 44 25 39 31 38 20 Yes F F No No No No F F F M F F M F F F Yes No Yes No No Yes No Yes No No Yes Yes Yes F F F M F No 8. Take a sample of 30 females from your data a. Show your sample b. Find the proportion of female cat owners out of these females 9. Take a sample of 30 males from your data a. Show your sample b. Find the proportion of male cat owners out of these males 10. Using the results of #8 and #9, test the claim that females have a higher proportion of cat ownership than males. a. State the null and alternative b. State the test statistic c. Use the p-value to make a decision (reject or fail to reject) d. Graph the test statistic, p-value, and a=0.05 e. Write your conclusion in terms of the problem Out of 117 People, only 42 People own cuts. I am going to use a systematic sampling 7 technique to draw a sample size of 30, starting from the second observation and ! 1) No Z) No 3) Yes 4) No 5) No 6) No 7) Yes 8) No 9) No 60) Yes 11) No 12) No 13) No 14) No 13) Yes IC) No 11) No ) No 19) Yes 20) No 21) No 22) No 23) No 24) Yes 25)Yes 26) No 27)No 28) Yes 29) No 30) No 31) No 32) Yes 33) No 34) Yes 35)No 36) No 57) Yes 38) No 39) No 40) No 41) Yes 42) No 43) Yes 44)No 45)80 46) Yes 47) No 43) Yes (41) No 50)NO 2) In this Sample 15 out of 50 People 4) Margin of Error = 1.96*10.3+0.7 own Cats, Proportion of Cat owners 30.127) 50 in the sample = 15-0.3 Confidence interval is expected to contain the the population proportion (3) 95%. Confidence internal is (Pt 26,95 st) 95 of the times. Only less than where Margin of Emor, M.E is 20.95*5.E 5% of the confidence interval is repeated sampling may not contain the true 5) Based on the sample it is hard to make population me such a belief. Again for the sake of doing. A) I believe that b5s of the People own cats, based on the belief in question 5,45% do not Cats, 6) My belief cannot be justified as the proportion is not contained in confidence interval calculated in question 3 c) According to the statement both evento (owning cuts and not owning Cats) are equally likely. It is 50% chance of owning the cat. Based on the population that I got in question 2 it doesn't look like they are equal. Dwn 7) To test Ho : P = 56% against H.P750s at br level of significance. The test statistic used in Z- P-P Where P in sample proportion &q=1-p&h=30 6) 2= 0.3-0.5 To 5x0.5 = 283 C) the quale which corresponds 50 to the zvate in 0.004620.05. The null hypothesis Can be rejected and a 5% alpha use conclude that the Proportion of cat owners is not obor bo% c) the critical wave from the d) Standard normal table at 5% level of significance is 11.96 of the test statistic, 2 vale is inside the interval. We would! have falled to reject the null -2.85 -1.96 hypothesis. The rejection region falls on the two extention of the test Statistic, which is shown in the graph above the value gets equally divided into two and show in the tails of distribution of test Statistic. 0.0023 0.0023 U 1.96 2.83 Benchmark 5- Cats and Dogs 1. From the sample of 50 you took from the previous benchmark (or you can just take a new sample of 50) record whether they owned a cat or not. You can use the table below, make another one, or use excel: 2. Find the proportion of people who own cats from this sample. 3. Create a 95% confidence interval for the true population proportion of cat owners based on your sample. In words write what the confidence interval means in terms of our data. 4. Find the margin of error for your confidence interval 5. If I believe that people are just as likely to own a cat than to not own a cat a. What do I believe the proportion or percentage of cat owners is? (For example is it 0.20 or 20% are cat owners? Or some other percentage?) b. Looking at the proportion from part (a), do you believe it is possible that the true proportion of cat owners is what I am claiming? Why or why not? (is it in the interval you made?) 6. Again I claim that people are just as likely to either own a cat or not own a cat. Based on the proportion you found in #2 do you believe I am correct? Or do you think the true proportion is more? Is it less? 7. Test my claim that people are just as likely to either own a cat or not versus what you stated in #6. Or if you believed that I am correct test my claim against the proportion just being different (not equal to my claim) than my claim. Use a significance level of a = 0.05. a. State the null and alternative b. State the test statistic Use the p-value to make a decision (reject or fail to reject) d. Graph the test statistic, p-value, and a e. Write your conclusion in terms of the problem C. Age Sex F M M M Own Cat Yes No No No Yes Yes F F Yes F M F M Own Dog Yes Yes Yes No No No Yes Yes No No No No No Yes F M F F No M M F M F No Yes No Yes No Yes Yes No No Yes No Yes Yes Yes No Yes No Yes No No No Yes Yes Yes No No No No No No Yes F F M F M F M M M F 64 75 55 36 64 56 60 23 59 75 62 30 55 58 41 25 64 32 57 62 64 67 57 40 58 53 53 23 55 64 56 19 19 58 58 69 40 55 No No Yes Yes Yes Yes No No Yes Yes No Yes No No No Yes Yes F Yes F M M M M M M F No Yes No Yes Yes F No Yes M M M M M M F M F F Yes No No No No No No Yes No Yes Yes Yes Yes Yes No Yes No No Yes No No No No No No No Yes Yes No No Yes No No No Yes No No Yes No No No 63 25 44 75 58 50 55 64 71 57 22 19 18 28 57 18 64 50 24 38 31 54 69 26 M M M M M M M M M F F No No F M F F M M No Yes No No No Yes Yes Yes Yes Yes No No Yes No No No No No Yes Yes Yes No No No No No 45 22 35 65 74 32 18 42 23 37 21 30 25 28 27 F F F M F F M No No No Yes No No Yes Yes Yes No Yes No No No F F F M Yes No No F F F M M F F F F M F F M M F F M No No Yes No No No Yes Yes No No No No Yes No No Yes Yes No No Yes No No No No No Yes No No Yes No No No No No No Yes No No No Yes Yes Yes No No No No Yes Yes Yes Yes Yes 69 26 44 45 22 35 65 74 32 18 42 23 37 21 30 25 28 27 37 33 40 70 20 26 38 43 42 49 22 28 39 53 67 44 25 39 31 38 20 Yes F F No No No No F F F M F F M F F F Yes No Yes No No Yes No Yes No No Yes Yes Yes F F F M F No

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