*Please show how you got the calculations.
In a reactor scenario, 20.000 g Fe3O4 was reacted, at 1450 K,with NO having an initial pressure of 3.000 atm. At equilibrium,the mass of the solid-phase product (Fe2O3) was calculated to be8.0742 g. 2Fe3O4(s) + 2NO(g) <=> 3Fe2O3(s) + N2O(g)
1. Calculate the mass of each gas-phase species atequilibrium.
2. Calculate the mass of Fe3O4 remaining at equilibrium from themass of Fe2O3 calculated to exist at equilibrium.
3. Calculate the total mass of all species at equilibrium andprove that it equals the initial total mass of the reactants, tothe .1 g place.
