Real Fruit Juice (Raw Data, SoftwareRequired):
A 32 ounce can of a popular fruit drink claims to contain 20%real fruit juice. Since this is a 32 ounce can, they areactually claiming that the can contains 6.4 ounces of realfruit juice. The consumer protection agency samples 30 suchcans of this fruit drink. The amount of real fruit juice in eachcan is given in the table below. Test the claim that the meanamount of real fruit juice in all 32 ounce cans is 6.4 ounces. Testthis claim at the 0.10 significance level.
(a) What type of test is this?This is a left-tailed test. This is a two-tailedtest. This is a right-tailed test.
(b) What is the test statistic? Round your answer to 2decimal places.
tx =
(c) Use software to get the P-value of the test statistic.Round to 4 decimal places.
P-value =
(d) What is the conclusion regarding the null hypothesis?reject H0 fail to rejectH0
(e) Choose the appropriate concluding statement.There is enough data to justify rejection of the claim that themean amount of real fruit juice in all 32 ounce cans is 6.4 ounces.There is not enough data to justify rejection of the claim that themean amount of real fruit juice in all 32 ounce cans is 6.4ounces. We have proven that the mean amountof real fruit juice in all 32 ounce cans is 6.4 ounces. We haveproven that the mean amount of real fruit juice in all 32 ouncecans is not 6.4 ounces. | DATA ( n = 30 )
Real Juice| ounces | | 6.28 | | 6.51 | | 6.52 | | 6.35 | | 6.23 | | 5.98 | | 6.25 | | 6.02 | | 6.07 | | 6.01 | | 6.47 | | 5.98 | | 6.47 | | 5.97 | | 6.61 | | 6.30 | | 6.50 | | 6.42 | | 5.93 | | 6.08 | | 6.19 | | 6.23 | | 5.76 | | 6.55 | | 5.68 | | 6.67 | | 6.42 | | 6.72 | | 6.28 | | 6.22 |
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