Starting from the one-dimensional motion equation x=Xo + vt prove that v^2 = Vo^2 + 2a(X-Xo) If...

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Question

Physics

Starting from the one-dimensional motion equation x=Xo + vt
prove that v^2 = Vo^2 + 2a(X-Xo)
If you could eplain as well why/ how each step in the problemproves the equation, this would be greatly helpful.
Thank you!

Answer & Explanation Solved by verified expert

3.7 Ratings (310 Votes)

As I previously said the gradient ofthe line is equal to acceleration a So avutRearranging this to make v the subject gives usour first constant acceleration formulasut12at2We know that the area See Answer

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Starting from the one-dimensional motion equation x=Xo + vt prove that v^2 = Vo^2 + 2a(X-Xo) If...

90.2K

Verified Solution

Question

Physics

Starting from the one-dimensional motion equation x=Xo + vt
prove that v^2 = Vo^2 + 2a(X-Xo)
If you could eplain as well why/ how each step in the problemproves the equation, this would be greatly helpful.
Thank you!

Answer & Explanation Solved by verified expert

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Starting from the one-dimensional motion equation x=Xo + vt prove that v^2 = Vo^2 + 2a(X-Xo) If...

90.2K

Verified Solution

Question

Physics

Starting from the one-dimensional motion equation x=Xo + vtprove that v^2 = Vo^2 + 2a(X-Xo)If you could eplain as well why/ how each step in the problemproves the equation, this would be greatly helpful.Thank you!

Answer & Explanation Solved by verified expert

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Other questions asked by students

Starting from the one-dimensional motion equation x=Xo + vt
prove that v^2 = Vo^2 + 2a(X-Xo)
If you could eplain as well why/ how each step in the problemproves the equation, this would be greatly helpful.
Thank you!