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  3. step 3 so far we have the following 10metric integ

Step 3 So far we have the following 10metric integral we put everything in terms...

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Calculus

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Step 3 So far we have the following 10metric integral we put everything in terms of sin 0 and cos 0 Doing so gives the following result cos 8 sec 4 sec 0 tan e de tan 8 3 Step 4 8 sec 4 u sec 4 3 3 We can now use the substitution u sin 0 so du cos 8 sin 8 sec 4 cos 8 sin 0 4 de 15 4 sec 2007 4 Jn 3 15 4 de 3 2 15 4 sin 0 cos 8 We have determined that if we let u sin 0 then du cos 8 de on the interval sin 0 du cos 6 de de Once more we must also make a substitution for the limits of integration When 15 Applying the substitution gives us the following result

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